$A$ galvanometer of resistance $36 \ \Omega$ is converted into an ammeter by using a shunt of $4 \ \Omega$. The fraction $f_0$ of the total current passing through the galvanometer is:

  • A
    $\frac{1}{40}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{140}$
  • D
    $\frac{1}{10}$

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Similar Questions

$A$ multirange current meter can be constructed by using a galvanometer circuit as shown in the figure. We want a current meter that can measure $10 \text{ mA}$,$100 \text{ mA}$,and $1 \text{ A}$ using a galvanometer of resistance $10 \text{ } \Omega$ that produces maximum deflection for a current of $1 \text{ mA}$. Find the values of $S_1, S_2$,and $S_3$ that have to be used.

What will be the resistance of the shunt when $5 \%$ of the main current is passed through a galvanometer of resistance $G$?

$A$ voltmeter has a resistance of $G \ \Omega$ and a range of $V \ \text{volt}$. The resistance required in series to convert it into a voltmeter of range $nV \ \text{volt}$ is . . . . . . .

$A$ galvanometer of resistance $40\,\Omega$ gives a deflection of $5\, \text{divisions}$ per $mA$. There are $50\, \text{divisions}$ on the scale. The maximum current that can pass through it when a shunt resistance of $2\,\Omega$ is connected is ................ $mA$.

The relation between voltage sensitivity $({\sigma _V})$ and current sensitivity $({\sigma _i})$ of a moving coil galvanometer is (Resistance of Galvanometer = $G$)

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