$A$ game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers $1, 2, 3, 4, 5, 6, 7, 8$ (see figure),and these are equally likely outcomes. What is the probability that it will point at:
$(i)$ $8?$
$(ii)$ an odd number?
$(iii)$ a number greater than $2?$
$(iv)$ a number less than $9?$

(N/A) The total number of possible outcomes is $8$ (i.e.,$1, 2, 3, 4, 5, 6, 7, 8$).
$(i)$ The number of favourable outcomes for getting $8$ is $1$.
Probability $= \frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{8}$.
$(ii)$ The odd numbers are $1, 3, 5, 7$. The number of favourable outcomes is $4$.
Probability $= \frac{4}{8} = \frac{1}{2}$.
$(iii)$ The numbers greater than $2$ are $3, 4, 5, 6, 7, 8$. The number of favourable outcomes is $6$.
Probability $= \frac{6}{8} = \frac{3}{4}$.
$(iv)$ All numbers $1, 2, 3, 4, 5, 6, 7, 8$ are less than $9$. The number of favourable outcomes is $8$.
Probability $= \frac{8}{8} = 1$.