$A$ game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers $1, 2, 3, \dots, 11, 12$ on a circular disc. All these outcomes are equally likely. Then, the probability that the arrow rests to point at $7$ is ..........
- A$\frac{7}{12}$
- B$\frac{5}{12}$
- C$\frac{1}{12}$
- D$\frac{1}{2}$
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