(A) According to Boyle's Law,for a fixed amount of gas at constant temperature,$P_1V_1 = P_2V_2$. Given: $P_1 = 10^4 \ Pa$,$V_1 = 100 \ cc$,$P_2 = 10^

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(A) According to Boyle's Law,for a fixed amount of gas at constant temperature,$P_1V_1 = P_2V_2$. Given: $P_1 = 10^4 \ Pa$,$V_1 = 100 \ cc$,$P_2 = 10^5 \ Pa$. Substituting the values: $10^4 \times 100 = 10^5 \times V_2$. $V_2 = \frac{10^4 \times 100}{10^5} = \frac{10^6}{10^5} = 10 \ cc$.

Class 11 Chemistry States of Matter Ideal gas equation and Related gas laws

Medium

$A$ gas of volume $100 \ cc$ is kept in a vessel at pressure $10^4 \ Pa$ maintained at temperature $24 \ ^oC$. If now the pressure is increased to $10^5 \ Pa$,keeping the temperature constant,then the volume of the gas becomes ............. $cc$.

A
$10$
B
$100$
C
$1$
D
$1000$

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States of Matter

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Ideal gas equation and Related gas laws

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$A$ gas of volume $100 \ cc$ is kept in a vessel at pressure $10^4 \ Pa$ maintained at temperature $24 \ ^oC$. If now the pressure is increased to $10^5 \ Pa$,keeping the temperature constant,then the volume of the gas becomes ............. $cc$.

Similar Questions

Assuming ideal gas behaviour,the ratio of density of ammonia to that of hydrogen chloride at the same temperature and pressure is: (Atomic wt. of $Cl = 35.5 \ u$)

$400 \ cm^{3}$ of oxygen at $27\,^{\circ}C$ were cooled to $-3\,^{\circ}C$ without change in pressure. The contraction in volume will be ............... $cm^{3}$

For the same mass of two different ideal gases of molecular weights $M_{1}$ and $M_{2}$, plots of $\log V$ vs $\log p$ at a given constant temperature are shown. Identify the correct option.

The pressure and temperature of $4 \ dm^3$ of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be ............. $dm^3$.

The isotherms of an ideal gas at $T_1, T_2, T_3$ along with their slopes $(m)$ are shown in the graph. If $T_1 > T_2 > T_3$,then the correct order of slopes of these isotherms is:

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