A gas present in a cylinder expands against a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The work done against constant external pressure is given by the formula $W = -P_{ext} \Delta V$. Given: $P_{ext} = 1 \, atm$,$V_1 = 2 \, L$,$V_2

Vedclass · Accepted Answer

$+395$

Vedclass · Answer

(C) The work done against constant external pressure is given by the formula $W = -P_{ext} \Delta V$. Given: $P_{ext} = 1 \, atm$,$V_1 = 2 \, L$,$V_2 = 6 \, L$,and $q = +800 \, J$ (heat absorbed). First,calculate the change in volume: $\Delta V = V_2 - V_1 = 6 \, L - 2 \, L = 4 \, L$. Convert the work done from $L \cdot atm$ to $J$ using the conversion factor $1 \, L \cdot atm = 101.325 \, J$: $W = -1 \, atm 	imes 4 \, L = -4 \, L \cdot atm = -4 	imes 101.325 \, J = -405.3 \, J$. According to the first law of thermodynamics: $\Delta U = q + W$. Substituting the values: $\Delta U = 800 \, J + (-405.3 \, J) = 394.7 \, J$. Rounding to the nearest integer,we get $\Delta U \approx 395 \, J$.

$A$ gas present in a cylinder expands against a constant pressure of $1 \, atm$ from a volume of $2 \, L$ to a volume of $6 \, L$. In doing so,it absorbs $800 \, J$ of heat from the surroundings. The change in internal energy of the process is ..... $J$.

Similar Questions

When $1 \, \text{mole}$ of monoatomic ideal gas at $T \, \text{K}$ undergoes adiabatic change under a constant external pressure of $1 \, \text{atm}$ and changes volume from $1 \, \text{L}$ to $2 \, \text{L}$,the final temperature in Kelvin would be:

In an adiabatic expansion of an ideal gas,which of the following relations holds true?

The first law of thermodynamics is only:

For an isothermal reversible expansion process,the value of $q$ can be calculated by the expression

One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of $27\, ^{\circ}C$. If the work done during the process is $3\, kJ$,then the final temperature of the gas is $(C_v = 20\, J\, K^{-1}\, mol^{-1})$ .....$K$

Vedclass Test Series

Exam Paper Generator

Online Exam Module