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(C) For an ideal transformer,the power input equals the power output,assuming no energy losses.The relationship is given by $V_p I_p = V_s I_s$,where

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$1.67$

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(C) For an ideal transformer,the power input equals the power output,assuming no energy losses.The relationship is given by $V_p I_p = V_s I_s$,where $V_p$ and $I_p$ are the primary voltage and current,and $V_s$ and $I_s$ are the secondary voltage and current.Given:Primary voltage $V_p = 4000 \, V$Primary current $I_p = 100 \, A$Secondary voltage $V_s = 240,000 \, V$Substituting the values into the equation:$4000 	imes 100 = 240,000 	imes I_s$$400,000 = 240,000 	imes I_s$$I_s = \frac{400,000}{240,000}$$I_s = \frac{40}{24} = \frac{5}{3} \approx 1.67 \, A$.

$A$ generator at a utility company produces $100 \, A$ of current at $4000 \, V$. The voltage is stepped up to $240,000 \, V$ by a transformer before it is sent on a high voltage transmission line. The current in the transmission line is ....... $A$.

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