A girl is carrying a school bag of 3 , kg mas | vedclass

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(A) Work done is defined as the product of force and displacement in the direction of the force,given by $W = F \cdot s \cdot \cos(	heta)$.Here,the g

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zero

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(A) Work done is defined as the product of force and displacement in the direction of the force,given by $W = F \cdot s \cdot \cos(	heta)$.Here,the gravitational force acts vertically downwards on the bag.The displacement of the girl is along the horizontal levelled road.Since the angle between the gravitational force (downward) and the displacement (horizontal) is $90^{\circ}$,the work done against gravity is $W = F \cdot s \cdot \cos(90^{\circ})$.Since $\cos(90^{\circ}) = 0$,the work done against the gravitational force is $0 \, J$.

$A$ girl is carrying a school bag of $3 \, kg$ mass on her back and moves $200 \, m$ on a levelled road. The work done against the gravitational force will be $(g = 10 \, m \, s^{-2})$.

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