A girl of mass 40, kg climbs a rope 6, m long | vedclass

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Question

(A) The power $P$ expended is defined as the rate of doing work,given by the formula $P = W / t$.Since the girl climbs at a constant speed,the work do

Vedclass · Accepted Answer

$156.8$

Vedclass · Answer

(A) The power $P$ expended is defined as the rate of doing work,given by the formula $P = W / t$.Since the girl climbs at a constant speed,the work done $W$ is equal to the change in potential energy,which is $W = mgh$.Given values are: mass $m = 40\, kg$,height $h = 6\, m$,and time $t = 15\, s$. Taking acceleration due to gravity $g = 9.8\, m/s^2$.Substituting these values into the formula:$P = \frac{mgh}{t} = \frac{40 	imes 9.8 	imes 6}{15} = \frac{2352}{15} = 156.8\, W$.Thus,the power expended by the girl is $156.8\, W$.

$A$ girl of mass $40\, kg$ climbs a rope $6\, m$ long at a constant speed in $15$ seconds. What power does she expend during the climb (in $W$)?

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