$A$ glass capillary tube of internal radius $r = 0.25 \, mm$ is immersed in water. The top end of the tube projects $2 \, cm$ above the surface of the water. At what angle does the liquid meet the tube (in $^{\circ}$)? (Surface tension of water $T = 0.07 \, N/m$,density $\rho = 1000 \, kg/m^3$,$g = 9.8 \, m/s^2$)

$A$ glass rod of radius $r_1$ is inserted symmetrically into a vertical capillary tube of radius $r_2$ $(r_1 < r_2)$ such that their lower ends are at the same level. The arrangement is dipped in water. The height to which water will rise into the tube will be ($\rho =$ density of water,$T =$ surface tension of water,$g =$ acceleration due to gravity).

Water rises in a capillary tube to a height such that the upward force of surface tension balances the downward force of $75 \times 10^{-4} \ N$ due to the weight of the water. If the surface tension of water is $12 \times 10^{-2} \ N/m$,the internal circumference of the capillary must be:

When a part of a straight capillary tube is placed vertically in a liquid, the liquid rises up to a certain height $h$. If the inner radius of the capillary tube, density of the liquid, and surface tension of the liquid decrease by $1\%$ each, then the height of the liquid in the tube will change by . . . . . . $\%$.

Water rises to height $h$ in a capillary tube. If the length of the capillary tube above the surface of water is made less than $h$,then

If water rises in a capillary tube up to $3 \, cm$,what is the diameter of the capillary tube? (Surface tension of water $T = 7.2 \times 10^{-2} \, N/m$,density $\rho = 10^3 \, kg/m^3$,$g = 10 \, m/s^2$)