A gramophone record is revolving with an angu | vedclass

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(D) For the coin to revolve with the record without slipping,the required centripetal force must be provided by the static frictional force.The centri

Vedclass · Accepted Answer

$R \leq \frac{\mu g}{\omega^2}$

Vedclass · Answer

(D) For the coin to revolve with the record without slipping,the required centripetal force must be provided by the static frictional force.The centripetal force required is $F_c = mR\omega^2$.The maximum static frictional force available is $f_{s,max} = \mu N = \mu mg$.For the coin to remain stationary relative to the record,the centripetal force must be less than or equal to the maximum static friction:$mR\omega^2 \leq \mu mg$Dividing both sides by $m\omega^2$,we get:$R \leq \frac{\mu g}{\omega^2}$

$A$ gramophone record is revolving with an angular velocity $\omega$. $A$ coin is placed at a distance $R$ from the centre of the record. The static coefficient of friction is $\mu$. The coin will revolve with the record if

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