A gulab jamun contains sugar syrup up to abou | vedclass

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(C) It can be observed that:Radius $(r)$ of cylindrical part $=$ Radius $(r)$ of hemispherical part $= \frac{2.8}{2} = 1.4\,cm$.Length of each hemisph

Vedclass · Accepted Answer

$338$

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(C) It can be observed that:Radius $(r)$ of cylindrical part $=$ Radius $(r)$ of hemispherical part $= \frac{2.8}{2} = 1.4\,cm$.Length of each hemispherical part $=$ Radius of hemispherical part $= 1.4\,cm$.Length $(h)$ of cylindrical part $= 5 - 2 	imes$ (Length of hemispherical part) $= 5 - 2 	imes 1.4 = 2.2\,cm$.Volume of one gulab jamun $=$ Volume of cylindrical part $+ 2 	imes$ Volume of hemispherical part$= \pi r^2 h + 2 	imes (\frac{2}{3} \pi r^3) = \pi r^2 h + \frac{4}{3} \pi r^3$$= \frac{22}{7} 	imes (1.4)^2 	imes 2.2 + \frac{4}{3} 	imes \frac{22}{7} 	imes (1.4)^3$$= 13.552 + 11.49866... \approx 25.05\,cm^3$.Volume of $45$ gulab jamuns $= 45 	imes 25.05 = 1127.25\,cm^3$.Volume of sugar syrup $= 30\%$ of total volume$= \frac{30}{100} 	imes 1127.25 = 338.175\,cm^3$.Rounding to the nearest whole number,the volume is approximately $338\,cm^3$.

$A$ gulab jamun contains sugar syrup up to about $30\%$ of its volume. Find approximately how much syrup would be found in $45$ gulab jamuns,each shaped like a cylinder with two hemispherical ends with length $5\,cm$ and diameter $2.8\,cm$ (see figure) (in $cm^3$) [take $\pi=\frac{22}{7}$].

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