A hall is 15 m long and 12 m broad. If the | vedclass

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(C) Let the length $l = 15 \ m$,breadth $b = 12 \ m$,and height be $h \ m$.The area of the floor and ceiling is $2 	imes (l 	imes b) = 2 	imes 15 \

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$1200$

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(C) Let the length $l = 15 \ m$,breadth $b = 12 \ m$,and height be $h \ m$.The area of the floor and ceiling is $2 	imes (l 	imes b) = 2 	imes 15 	imes 12 = 360 \ m^2$.The area of the four walls is $2 	imes (l + b) 	imes h = 2 	imes (15 + 12) 	imes h = 54h \ m^2$.According to the problem,the sum of the areas of the floor and ceiling equals the sum of the areas of the four walls:$360 = 54h$.$h = \frac{360}{54} = \frac{20}{3} \ m$.The volume of the hall is $V = l 	imes b 	imes h = 15 	imes 12 	imes \frac{20}{3}$.$V = 180 	imes \frac{20}{3} = 60 	imes 20 = 1200 \ m^3$.

$A$ hall is $15 \ m$ long and $12 \ m$ broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of the four walls,the volume of the hall is: (in $m^3$)

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