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(C) Given:Blood pressure at heart level,$P_{	ext{heart}} = 13.3 \,kPa = 13300 \,Pa$.Density of blood,$ho = 10^3 \,kg/m^3$.Acceleration due to gravi

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(C) Given:Blood pressure at heart level,$P_{	ext{heart}} = 13.3 \,kPa = 13300 \,Pa$.Density of blood,$ho = 10^3 \,kg/m^3$.Acceleration due to gravity,$g = 10 \,m/s^2$.Height of heart from foot,$h_1 = 1.3 \,m$.Height of head from heart,$h_2 = 1.7 \,m - 1.3 \,m = 0.4 \,m$.Pressure at the foot level is given by $P_{	ext{foot}} = P_{	ext{heart}} + ho g h_1$.$P_{	ext{foot}} = 13300 + (10^3 	imes 10 	imes 1.3) = 13300 + 13000 = 26300 \,Pa = 26.3 \,kPa$.Pressure at the head level is given by $P_{	ext{head}} = P_{	ext{heart}} - ho g h_2$.$P_{	ext{head}} = 13300 - (10^3 	imes 10 	imes 0.4) = 13300 - 4000 = 9300 \,Pa = 9.3 \,kPa$.The ratio of $BP$ in the foot region to that in the head region is:$	ext{Ratio} = \frac{P_{	ext{foot}}}{P_{	ext{head}}} = \frac{26.3}{9.3} \approx 2.828$.This value is closest to $3$.

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