A hemispherical bowl has a radius of 3.5, cm. | vedclass

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Question

(A) The volume of a hemispherical bowl is given by the formula $V = \frac{2}{3} \pi r^{3}$.Given the radius $r = 3.5\, cm = \frac{7}{2}\, cm$.Substitu

Vedclass · Accepted Answer

$89.83$

Vedclass · Answer

(A) The volume of a hemispherical bowl is given by the formula $V = \frac{2}{3} \pi r^{3}$.Given the radius $r = 3.5\, cm = \frac{7}{2}\, cm$.Substituting the values:$V = \frac{2}{3} 	imes \frac{22}{7} 	imes (\frac{7}{2})^{3}$$V = \frac{2}{3} 	imes \frac{22}{7} 	imes \frac{7}{2} 	imes \frac{7}{2} 	imes \frac{7}{2}$$V = \frac{1}{3} 	imes 11 	imes \frac{49}{2} = \frac{539}{6} \approx 89.83\, cm^{3}$.

$A$ hemispherical bowl has a radius of $3.5\, cm$. What would be the volume of water it would contain (in $, cm^{3}$)?

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