A body weighs 63 , N on the surface of the ea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. First,calculate the mass of the body $(m)$. Given weight $W = mg = 63 \, N$. Assuming $g = 10 \, m/s^2$,$m = 63 / 10 = 6.3 \, kg$.$2$. The di

Vedclass · Accepted Answer

$27.35$

Vedclass · Answer

(A) $1$. First,calculate the mass of the body $(m)$. Given weight $W = mg = 63 \, N$. Assuming $g = 10 \, m/s^2$,$m = 63 / 10 = 6.3 \, kg$.$2$. The distance of the body from the center of the earth $(r)$ at a height $h = R/2$ is $r = R + h = R + R/2 = 1.5R$.$3$. Given $R = 6.4 	imes 10^6 \, m$,so $r = 1.5 	imes 6.4 	imes 10^6 = 9.6 	imes 10^6 \, m$.$4$. The gravitational force is given by $F = \frac{GMm}{r^2}$.$5$. Substituting the values: $F = \frac{6.67 	imes 10^{-11} 	imes 6 	imes 10^{24} 	imes 6.3}{(9.6 	imes 10^6)^2}$.$6$. $F = \frac{252.186 	imes 10^{13}}{92.16 	imes 10^{12}} = \frac{2521.86}{92.16} \approx 27.35 \, N$.

$A$ body weighs $63 \, N$ on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth (in $, N$)? (Given: Mass of the earth $= 6 \times 10^{24} \, kg$ and radius of the earth $= 6.4 \times 10^{6} \, m$)

Similar Questions

$A$ stone is dropped from a cliff. Its speed after it has fallen $100 \,m$ is: (in $, m s^{-1}$)

What is meant by free fall? Two bodies,one of mass $1\,g$ and other of mass $1\,kg$,are dropped from the same height in a vacuum. Compare the two time intervals in which the two bodies will hit the ground.

What do you mean by free fall?

Show mathematically that the acceleration experienced by an object during free fall is independent of the mass of the object.

State two factors on which the value of $g$ depends.

Vedclass Test Series

Exam Paper Generator

Online Exam Module