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Question

(D) For a conducting material in electrostatic equilibrium,the electric field inside the material is zero. This implies that the potential is constant

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potential at $A, B, C$ and $O$ is same

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(D) For a conducting material in electrostatic equilibrium,the electric field inside the material is zero. This implies that the potential is constant throughout the volume of the conductor.Points $A$ and $B$ lie within the material of the conducting sphere,therefore $V_A = V_B$.Furthermore,the electric field inside the cavity of a hollow conductor is zero if there is no charge inside the cavity. Since the electric field $E = -dV/dr = 0$,the potential $V$ must be constant throughout the cavity and equal to the potential at the inner surface of the conductor.Thus,the potential at all points $O, C, A,$ and $B$ is the same,i.e.,$V_O = V_C = V_A = V_B$.

$A$ hollow conducting sphere of inner radius $R$ and outer radius $2R$ is given a charge $Q$ as shown in the figure. Then,which of the following is true?

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