A hollow cylinder of height 3,cm is recast in | vedclass

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(B) Let the radius of the solid cylinder be $r\,cm$ and its height be $H = 9\,cm$ (assuming the height of the solid cylinder is $9\,cm$ based on the v

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$2.4$

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(B) Let the radius of the solid cylinder be $r\,cm$ and its height be $H = 9\,cm$ (assuming the height of the solid cylinder is $9\,cm$ based on the volume calculation provided).The volume of the hollow cylinder is given by $V = \pi(R^2 - r_{in}^2)h$,where $R = 4.3\,cm$,$r_{in} = 1.1\,cm$,and $h = 3\,cm$.$V = \pi(4.3^2 - 1.1^2) 	imes 3 = \pi(18.49 - 1.21) 	imes 3 = \pi(17.28) 	imes 3 = 51.84\pi\,cm^3$.The volume of the solid cylinder is $V = \pi r^2 H$. Given $H = 9\,cm$:$51.84\pi = \pi r^2 	imes 9$.$r^2 = \frac{51.84}{9} = 5.76$.$r = \sqrt{5.76} = 2.4\,cm$.

$A$ hollow cylinder of height $3\,cm$ is recast into a solid cylinder. If the external and internal radii of the hollow cylinder are $4.3\,cm$ and $1.1\,cm$ respectively,what will be the radius of the solid cylinder? (in $cm$)

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