A homogeneous electric field vec{E} and a uni | vedclass

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(A) The force on a charged particle moving in combined electric and magnetic fields is given by the Lorentz force equation: $\vec{F} = q(\vec{E} + \ve

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Go on moving in the same direction with increasing velocity

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(A) The force on a charged particle moving in combined electric and magnetic fields is given by the Lorentz force equation: $\vec{F} = q(\vec{E} + \vec{v} 	imes \vec{B})$.Since the proton is projected with its velocity $\vec{v}$ parallel to the electric field $\vec{E}$ and the magnetic field $\vec{B}$ is in the same direction as $\vec{E}$,the velocity $\vec{v}$ is also parallel to $\vec{B}$.The magnetic force $\vec{F}_m = q(\vec{v} 	imes \vec{B}) = 0$ because the angle between $\vec{v}$ and $\vec{B}$ is $0^\circ$.The electric force $\vec{F}_e = q\vec{E}$ acts on the proton in the direction of the electric field,which is the same as the direction of its initial velocity.Since there is a constant force acting in the direction of motion,the proton will continue to move in the same direction with an increasing velocity.

$A$ homogeneous electric field $\vec{E}$ and a uniform magnetic field $\vec{B}$ are pointing in the same direction. $A$ proton is projected with its velocity parallel to $\vec{E}$. It will

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