A horizontal overhead powerline is at a heigh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The magnetic field $B$ due to a long straight current-carrying wire at a distance $R$ is given by the formula:$B = \frac{{\mu _0} I}{2 \pi R}$Give

Vedclass · Accepted Answer

$5 	imes {10^{ - 6}}\,T$ southward

Vedclass · Answer

(C) The magnetic field $B$ due to a long straight current-carrying wire at a distance $R$ is given by the formula:$B = \frac{{\mu _0} I}{2 \pi R}$Given:$I = 100\,A$$R = 4\,m$${\mu _0} = 4\pi 	imes {10^{ - 7}}\,TmA^{-1}$Substituting the values:$B = \frac{{4\pi 	imes {{10}^{ - 7}} 	imes 100}}{{2\pi 	imes 4}}$$B = \frac{{2 	imes {{10}^{ - 7}} 	imes 100}}{4}$$B = \frac{{2 	imes {{10}^{ - 5}}}}{4} = 0.5 	imes {10^{ - 5}} = 5 	imes {10^{ - 6}}\,T$Using the Right-Hand Thumb Rule,for a current flowing from east to west,the magnetic field lines below the wire point towards the south.

$A$ horizontal overhead powerline is at a height of $4\,m$ from the ground and carries a current of $100\,A$ from east to west. The magnetic field directly below it on the ground is $\left( {{\mu _0} = 4\pi \times {{10}^{ - 7}}} \right)TmA^{-1}$.

Similar Questions

The magnetic field at a perpendicular distance of $1 \,m$ from a long straight wire carrying a current of $1 \,A$ is:

$A$ thin ring of radius $R$ carries a uniformly distributed charge. The ring rotates at a constant speed $N$ r.p.s. about its axis perpendicular to the plane. If $B$ is the magnetic field at the centre,the charge on the ring is ($\mu_0 =$ permeability of free space).

$A$ current carrying circular coil of radius $R$ produces magnetic field $B_1$ at an axial point $P$ at a distance $x$ from its centre and $B_2$ at point $Q$ placed at its centre respectively. If $B_2 = 8B_1$, the value of $x$ is

An infinitely long straight conductor is bent into the shape as shown in the figure. It carries a current $I$ and the radius of the circular loop is $r$. The magnetic induction at the center $O$ of the circular loop is:

In a hydrogen atom,an electron is revolving at $6.6 \times 10^{15} \text{ rev/s}$ around the nucleus in an orbit of radius $0.47 \text{ Å}$. The magnetic field induction produced at the centre of the orbit is nearly: (in $\text{ Wb m}^{-2}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module