$A$ horizontal right-angle pipe bend has a cross-sectional area of $10 \ cm^2$ and water flows through it at a speed of $20 \ m/s$. The force on the pipe bend due to the turning of water is ........ $N$.

$A$ stream of water flowing horizontally with a speed of $15\; m s^{-1}$ gushes out of a tube of cross-sectional area $10^{-2}\; m^2$,and hits a vertical wall nearby. What is the force in $N$ exerted on the wall by the impact of water,assuming it does not rebound?

$A$ tube of length $L$ is filled completely with an incompressible liquid of mass $M$ and closed at both the ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity $\omega$. The force exerted by the liquid at the other end is

$A$ gardener waters the plants using a pipe of diameter $1\,mm$. The water comes out at a rate of $10\,cm^3/s$. The reactionary force exerted on the hand of the gardener is:

$A$ tube of length $50\,cm$ is filled completely with an incompressible liquid of mass $250\,g$ and closed at both ends. The tube is then rotated in a horizontal plane about one of its ends with a uniform angular velocity $\omega = x \sqrt{F} \text{ rad } s^{-1}$. If $F$ is the force exerted by the liquid at the other end,then the value of $x$ will be: