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(D) The power supplied by the circuit is given by $P = V 	imes I$. Given,$V = 220 \, V$ and $I = 9 \, A$. Total power $P = 220 	imes 9 = 1980 \, W$.

Vedclass · Accepted Answer

$33$

Vedclass · Answer

(D) The power supplied by the circuit is given by $P = V 	imes I$. Given,$V = 220 \, V$ and $I = 9 \, A$. Total power $P = 220 	imes 9 = 1980 \, W$. Let $n$ be the number of $60 \, W$ lamps connected in parallel. The total power consumed by $n$ lamps is $n 	imes 60 \, W$. For the fuse not to blow,the total power consumed must be less than or equal to the supply power: $n 	imes 60 \leq 1980$. $n \leq \frac{1980}{60} = 33$. Therefore,the maximum number of lamps that can be turned on is $33$.

$A$ house is served by a $220 \, V$ supply line in a circuit protected by a $9 \, A$ fuse. What is the maximum number of $60 \, W$ lamps in parallel that can be turned on simultaneously?

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