A hydrocarbon having molecular formula C_5H_{ | vedclass

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(C) The hydrocarbon with molecular formula $C_5H_{10}$ is an alkene. Acid-catalyzed hydration of $2$-methyl$-2$-butene $(CH_3-C(CH_3)=CH-CH_3)$ follow

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$2$-methyl$-2$-butene

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(C) The hydrocarbon with molecular formula $C_5H_{10}$ is an alkene. Acid-catalyzed hydration of $2$-methyl$-2$-butene $(CH_3-C(CH_3)=CH-CH_3)$ follows Markovnikov's rule to form $2$-methyl$-2$-butanol,which is a tertiary $(3^{\circ})$ alcohol. Oxidative cleavage of $2$-methyl$-2$-butene with acidic $KMnO_4$ breaks the double bond to produce acetone $(CH_3COCH_3)$ and acetic acid $(CH_3COOH)$,which are a ketone and a carboxylic acid respectively. Therefore,the correct hydrocarbon is $2$-methyl$-2$-butene.

$A$ hydrocarbon having molecular formula $C_5H_{10}$ produced a tertiary alcohol upon treatment with a few drops of conc. sulphuric acid and water. The same hydrocarbon when reacted with acidic potassium permanganate produced a ketone and a carboxylic acid. The hydrocarbon is $....$

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