A ladder having a length of 16,m is leaning a | vedclass

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(C) Let the ladder be represented by $AB$,where $AB = 16\,m$ is the length of the ladder.Let $AC$ be the distance between the foot of the ladder $(A)$

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(C) Let the ladder be represented by $AB$,where $AB = 16\,m$ is the length of the ladder.Let $AC$ be the distance between the foot of the ladder $(A)$ and the wall $(C)$.In the right-angled triangle $ABC$,the angle with the ground is $\angle A = 60^{\circ}$.Using the trigonometric ratio $\cos 	heta = \frac{	ext{base}}{	ext{hypotenuse}}$,we have:$\cos 60^{\circ} = \frac{AC}{AB}$$\frac{1}{2} = \frac{AC}{16}$$AC = 16 	imes \frac{1}{2} = 8\,m$.Therefore,the distance between the wall and the foot of the ladder is $8\,m$.

$A$ ladder having a length of $16\,m$ is leaning against a wall at an angle of $60^{\circ}$ with the ground. Find the distance between the wall and the foot of the ladder (in $m$).

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