$A$ large number of water drops,each of radius $r$,combine to form a single drop of radius $R$. If the surface tension is $T$ and the mechanical equivalent of heat is $J$,then the rise in temperature will be:

  • A
    $\frac{2T}{rJ}$
  • B
    $\frac{3T}{RJ}$
  • C
    $\frac{3T}{J} \left( \frac{1}{r} - \frac{1}{R} \right)$
  • D
    $\frac{2T}{J} \left( \frac{1}{r} - \frac{1}{R} \right)$

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