A letter of English alphabets is chosen at ra | vedclass

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(B) We know that in the English alphabet,there are $5$ vowels and $21$ consonants,making a total of $26$ letters.The total number of possible outcomes

Vedclass · Accepted Answer

$\frac{21}{26}$

Vedclass · Answer

(B) We know that in the English alphabet,there are $5$ vowels and $21$ consonants,making a total of $26$ letters.The total number of possible outcomes is $n(S) = 26$.Let $E$ be the event of choosing a consonant from the English alphabet.The set of consonants is ${b, c, d, f, g, h, j, k, l, m, n, p, q, r, s, t, v, w, x, y, z}$.Therefore,the number of favorable outcomes is $n(E) = 21$.The probability of an event is given by $P(E) = \frac{n(E)}{n(S)}$.Thus,the required probability is $\frac{21}{26}$.

$A$ letter of English alphabets is chosen at random. Determine the probability that the letter is a consonant.

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