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(C) Given,$(dn/dy) > 0$. This means the refractive index $n$ increases as we move in the positive $y$-direction.Let $AB$ be the incident wavefront,whe

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bending upward

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(C) Given,$(dn/dy) > 0$. This means the refractive index $n$ increases as we move in the positive $y$-direction.Let $AB$ be the incident wavefront,where $A$ is at a higher $y$-coordinate than $B$.Since the refractive index $n$ is higher at $A$ than at $B$,the speed of light $v = c/n$ is lower at $A$ than at $B$.As the wavefront passes through the medium of thickness $t$,the part of the wavefront at $B$ travels faster than the part at $A$.Consequently,the wavefront rotates such that the end at $B$ advances further than the end at $A$,causing the emerging light beam to bend upward.

$A$ light beam travelling along the $X$-axis with a planar wavefront is incident on a medium of thickness $t$. In the region where light is falling,the refractive index varies such that $(dn/dy) > 0$. The light beam on the other side of the medium will emerge:

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