A light bulb,a capacitor,and a battery are co | vedclass

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(A) When the switch $S$ is closed,the capacitor begins to charge. Initially,the capacitor acts as a short circuit (zero resistance),allowing current t

Vedclass · Accepted Answer

The bulb will light up for an instant when the capacitor starts charging.

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(A) When the switch $S$ is closed,the capacitor begins to charge. Initially,the capacitor acts as a short circuit (zero resistance),allowing current to flow through the circuit,which causes the bulb to light up for an instant. As the capacitor charges,the potential difference across it increases,and the current in the circuit decreases. Once the capacitor is fully charged,it acts as an open circuit,blocking the flow of direct current $(DC)$. Therefore,the current becomes zero,and the bulb stops glowing.

$A$ light bulb,a capacitor,and a battery are connected in a series circuit as shown in the figure,with switch $S$ initially open. When the switch $S$ is closed,which one of the following is true?

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