A liquid X of density 3.36 , g/cm^3 is poured | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the density of liquid $X$ be $\rho_X = 3.36 \, g/cm^3$, the density of liquid $Y$ be $\rho_Y$, and the density of mercury be $\rho_{Hg} = 13.6

Vedclass · Accepted Answer

$0.8$

Vedclass · Answer

(A) Let the density of liquid $X$ be $ho_X = 3.36 \, g/cm^3$, the density of liquid $Y$ be $ho_Y$, and the density of mercury be $ho_{Hg} = 13.6 \, g/cm^3$.At the same horizontal level in a continuous static fluid, the pressure is equal.Let the common interface level be the reference level. In the right arm, the pressure at this level is due to the column of liquid $X$ of height $h_X = 10 \, cm$.In the left arm, the pressure at this level is due to the column of liquid $Y$ of height $h_Y = 8 \, cm$ plus the pressure due to the mercury column of height $h_{Hg} = (10 - 8) \, cm = 2 \, cm$.Equating the pressures at this level:$P_{right} = P_{left}$$ho_X g h_X = ho_Y g h_Y + ho_{Hg} g h_{Hg}$$3.36 	imes 10 = ho_Y 	imes 8 + 13.6 	imes 2$$33.6 = 8 ho_Y + 27.2$$8 ho_Y = 33.6 - 27.2$$8 ho_Y = 6.4$$ho_Y = 0.8 \, g/cm^3$.

Similar Questions

$A$ uniform long tube is bent into a circle of radius $R$ and it lies in a vertical plane. Two liquids of the same volume but densities $\rho$ and $\delta$ fill half the tube. The angle $\theta$ is

$A$ $U$ tube contains water and methylated spirit separated by mercury. The mercury columns in the two arms are at the same level with $10\,cm$ of water in one arm and $12.5\,cm$ of spirit in the other,as shown in the figure. The relative density of the spirit is

Why is the dam of a water reservoir thick at the bottom?

Two stretched membranes of area $2\, cm^2$ and $3\, cm^2$ are placed in a liquid at the same depth. The ratio of pressures on them is

Vedclass Test Series

Exam Paper Generator

Online Exam Module