A magnet of magnetic moment 50 hat{i} text{ A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The torque $\vec{	au}$ acting on a magnetic dipole in a magnetic field is given by the cross product: $\vec{	au} = \vec{\mu} 	imes \vec{B}$.Giv

Vedclass · Accepted Answer

$150 \hat{k} 	ext{ Nm}$

Vedclass · Answer

(B) The torque $\vec{	au}$ acting on a magnetic dipole in a magnetic field is given by the cross product: $\vec{	au} = \vec{\mu} 	imes \vec{B}$.Given:$\vec{\mu} = 50 \hat{i} 	ext{ Am}^2$$\vec{B} = (0.5 \hat{i} + 3.0 \hat{j}) 	ext{ T}$Substituting the values:$\vec{	au} = (50 \hat{i}) 	imes (0.5 \hat{i} + 3.0 \hat{j})$Using the distributive property of the cross product:$\vec{	au} = (50 	imes 0.5) (\hat{i} 	imes \hat{i}) + (50 	imes 3.0) (\hat{i} 	imes \hat{j})$Since $\hat{i} 	imes \hat{i} = 0$ and $\hat{i} 	imes \hat{j} = \hat{k}$:$\vec{	au} = 0 + 150 \hat{k} 	ext{ Nm}$$\vec{	au} = 150 \hat{k} 	ext{ Nm}$.

$A$ magnet of magnetic moment $50 \hat{i} \text{ Am}^2$ is placed along the $x$-axis in a magnetic field $\vec{B} = (0.5 \hat{i} + 3.0 \hat{j}) \text{ T}$. The torque acting on the magnet is:

Similar Questions

$A$ bar magnet has a magnetic moment of $200 \text{ A m}^2$. The magnet is suspended in a magnetic field of $0.30 \text{ N A}^{-1} \text{ m}^{-1}$. The torque required to rotate the magnet from its equilibrium position through an angle of $30^{\circ}$ will be:

If the dipole moment of a short bar magnet is $1.25 \ A-m^2$,find the magnetic field on its axis at a distance of $0.5 \ m$ from the centre of the magnet.

$A$ magnet of length $10 \text{ cm}$ and magnetic moment $1 \text{ Am}^2$ is placed along side $AB$ of an equilateral triangle $ABC$. If the length of the side $AB$ is $10 \text{ cm}$, find the magnetic induction at point $C$. (Given $\mu_0 = 4\pi \times 10^{-7} \text{ Hm}^{-1}$)

Two identical magnetic dipoles of magnetic moments $1.0 \, A-m^2$ each are placed at a separation of $2 \, m$ with their axes perpendicular to each other. The resultant magnetic field at a point $P$ midway between the dipoles is:

$A$ magnet suspended in a uniform magnetic field is heated so as to reduce its magnetic moment by $19 \%$. By doing this,the time period of the magnet approximately

Vedclass Test Series

Exam Paper Generator

Online Exam Module