$A$ magnetic needle is kept in a non-uniform magnetic field. It experiences

$A$ metal wire of length $l$ has a magnetic moment $M$. What is the new magnetic moment if it is bent into an $L$-shape?

$A$ cylindrical magnetic rod has length $5 \ cm$ and diameter $1 \ cm$. It has uniform magnetization $M = 5.3 \times 10^{3} \ A/m$. Its net magnetic dipole moment is nearly (take $\pi = 22/7$):

$A$ magnetised wire of magnetic moment $3.14 \, A-m^2$ is bent in the form of a semi-circle. The new magnetic moment will be.....$A-m^2$

Two equal bar magnets are kept as shown in the figure. The direction of the resultant magnetic field,indicated by the arrow head at the point $P$,is (approximately):

In the case of a bar magnet,lines of magnetic induction: