A man buys two chairs for a total cost of 900 | vedclass

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(D) Let the cost price $(C.P.)$ of the first chair be $₹ x$ and the $C.P.$ of the second chair be $₹(900 - x)$.According to the problem,the selling pr

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$300$

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(D) Let the cost price $(C.P.)$ of the first chair be $₹ x$ and the $C.P.$ of the second chair be $₹(900 - x)$.According to the problem,the selling price $(S.P.)$ of the first chair is $\frac{4}{5}x$ (a loss of $\frac{1}{5}x$) and the $S.P.$ of the second chair is $\frac{5}{4}(900 - x)$ (a profit of $\frac{1}{4}(900 - x)$).The total profit is given as $₹90$.Total $S.P. - Total C.P. = Profit$$(\frac{4}{5}x + \frac{5}{4}(900 - x)) - 900 = 90$$\frac{4}{5}x + 1125 - \frac{5}{4}x = 990$$1125 - 990 = \frac{5}{4}x - \frac{4}{5}x$$135 = \frac{25x - 16x}{20}$$135 = \frac{9x}{20}$$x = \frac{135 	imes 20}{9} = 15 	imes 20 = 300$.The cost of the first chair is $₹300$ and the cost of the second chair is $900 - 300 = ₹600$.The lower priced chair costs $₹300$.

$A$ man buys two chairs for a total cost of $900$. By selling one for $\frac{4}{5}$ of its cost and the other for $\frac{5}{4}$ of its cost,he makes a profit of $90$ on the whole transaction. The cost of the lower priced chair is (in $Rs.$)

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