$A$ man can see objects clearly between $15 \ cm$ and $30 \ cm$. He uses a lens to see far objects. Due to the lens used,the new near point will be at........$cm$.

  • A
    $\frac{10}{3}$
  • B
    $30$
  • C
    $15$
  • D
    $\frac{100}{3}$

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