A man deposited Rs. 10000 in a bank at the ra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The principal amount $P = Rs. 10000$ and the annual simple interest $I = \frac{5}{100} 	imes 10000 = Rs. 500$.The amount in the $n^{	ext{th}}$ y

Vedclass · Accepted Answer

$Rs. 17000$ and $Rs. 20000$

Vedclass · Answer

(A) The principal amount $P = Rs. 10000$ and the annual simple interest $I = \frac{5}{100} 	imes 10000 = Rs. 500$.The amount in the $n^{	ext{th}}$ year is given by $A_n = P + (n-1)I$.For the $15^{	ext{th}}$ year,$n = 15$:$A_{15} = 10000 + (15-1) 	imes 500 = 10000 + 14 	imes 500 = 10000 + 7000 = Rs. 17000$.The total amount after $20$ years is the amount at the end of the $20^{	ext{th}}$ year:$A_{20} = P + 20 	imes I = 10000 + 20 	imes 500 = 10000 + 10000 = Rs. 20000$.

$A$ man deposited $Rs. 10000$ in a bank at the rate of $5\%$ simple interest annually. Find the amount in the $15^{\text{th}}$ year since he deposited the amount and also calculate the total amount after $20$ years.

Similar Questions

Let $A_1, A_2, \dots, A_{39}$ be $39$ arithmetic means between the numbers $59$ and $159$. Then the mean of $A_{25}, A_{28}, A_{31}$ and $A_{36}$ is equal to:

Let $AP(a; d)$ denote the set of all the terms of an infinite arithmetic progression with first term $a$ and common difference $d > 0$. If $AP(1; 3) \cap AP(2; 5) \cap AP(3; 7) = AP(a; d)$,then $a + d$ equals:

If the sum and product of the first three terms in an $A.P.$ are $33$ and $1155$,respectively,then a value of its $11^{th}$ term is

What is the sum of $n$ arithmetic means between $a$ and $b$?

If $A_1, A_2$ are two arithmetic means between $\frac{1}{3}$ and $\frac{1}{24}$,then their values are

Vedclass Test Series

Exam Paper Generator

Online Exam Module