A man has some hens and cows. If the number o | vedclass

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(D) Let the number of hens be $x$ and the number of cows be $y$.Since each animal has one head,we have: $x + y = 48$ (Equation $1$).Since a hen has $2

Vedclass · Accepted Answer

$26$

Vedclass · Answer

(D) Let the number of hens be $x$ and the number of cows be $y$.Since each animal has one head,we have: $x + y = 48$ (Equation $1$).Since a hen has $2$ legs and a cow has $4$ legs,we have: $2x + 4y = 140$ (Equation $2$).From Equation $1$,$y = 48 - x$.Substitute this into Equation $2$: $2x + 4(48 - x) = 140$.$2x + 192 - 4x = 140$.$-2x = 140 - 192$.$-2x = -52$.$x = 26$.Therefore,the number of hens is $26$.

$A$ man has some hens and cows. If the number of heads is $48$ and the number of legs is $140$,then the number of hens is:

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