A man is at a distance d behind a bus. The bu | vedclass

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(C) Let us analyze the relative motion of the man with respect to the bus. Let the bus be at rest. The man has an initial velocity $v$ and an accelera

Vedclass · Accepted Answer

Both $(a)$ and $(b)$ are correct.

Vedclass · Answer

(C) Let us analyze the relative motion of the man with respect to the bus. Let the bus be at rest. The man has an initial velocity $v$ and an acceleration $-a$ relative to the bus.The man will catch the bus if his displacement $s$ relative to the bus is at least $d$. Using the equation of motion $v_f^2 = v_i^2 + 2as$:$0 = v^2 - 2ad_{rel}$$0 = v^2 - 2ad$$v^2 = 2ad \implies v = \sqrt{2ad}$Thus,the man catches the bus if $v \geq \sqrt{2ad}$. Statement $(a)$ is correct.To find the time taken when he just catches the bus,we use $v_f = v_i + at$:$0 = v - at$$t = \frac{v}{a}$Statement $(b)$ is also correct.Therefore,both $(a)$ and $(b)$ are correct.

$A$ man is at a distance $d$ behind a bus. The bus starts from rest and moves away from the man with a constant acceleration $a$. At the same time,the man starts running towards the bus with a constant velocity $v$. Which of the following statements are correct?

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