A man known to be a victim of haemophilia mar | vedclass

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Question

(B) Haemophilia is an $X$-linked recessive disorder.Let $X^h$ represent the haemophilic allele and $X$ represent the normal allele.The man is a victim

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Half of their children will be bleeders

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(B) Haemophilia is an $X$-linked recessive disorder.Let $X^h$ represent the haemophilic allele and $X$ represent the normal allele.The man is a victim of haemophilia,so his genotype is $X^hY$.The woman is normal but her father was a bleeder $(X^hY)$,which means she must have inherited the $X^h$ allele from him. Thus,her genotype is $X^hX$.When they marry,the cross is $X^hY 	imes X^hX$.The possible offspring genotypes are:$1. X^hX^h$ (Haemophilic daughter)$2. X^hX$ (Carrier daughter)$3. X^hY$ (Haemophilic son)$4. XY$ (Normal son)Out of these four possibilities,two are affected (haemophilic). Therefore,half of their children will be bleeders.

$A$ man known to be a victim of haemophilia marries a normal woman whose father was known to be a bleeder. Then it is expected that:

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