A man moves towards a plane mirror with a vel | vedclass

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(B) The velocity of the man perpendicular to the mirror is $v_{\perp} = v \cos 	heta$.The image formed by a plane mirror moves in the opposite direct

Vedclass · Accepted Answer

$2\,v\,\cos\,	heta$

Vedclass · Answer

(B) The velocity of the man perpendicular to the mirror is $v_{\perp} = v \cos 	heta$.The image formed by a plane mirror moves in the opposite direction with the same speed perpendicular to the mirror.Thus,the velocity of the image perpendicular to the mirror is $v'_{image} = -v \cos 	heta$.The relative velocity of the image with respect to the man in the direction normal to the mirror is $v_{rel} = v_{image} - v_{man} = (-v \cos 	heta) - (v \cos 	heta) = -2v \cos 	heta$.The magnitude of this relative velocity is $|-2v \cos 	heta| = 2v \cos 	heta$.

$A$ man moves towards a plane mirror with a velocity $v$ in a direction making an angle $\theta$ with the normal to the mirror. The magnitude of the velocity of the image relative to the man normal to the mirror will be

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