A man runs across the roof of a tall building | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given:Horizontal speed of the man,$u_x = 9 \, m/s$Horizontal distance between the two buildings,$x = 10 \, m$Vertical height difference,$h = 9 \,

Vedclass · Accepted Answer

Yes

Vedclass · Answer

(A) Given:Horizontal speed of the man,$u_x = 9 \, m/s$Horizontal distance between the two buildings,$x = 10 \, m$Vertical height difference,$h = 9 \, m$Acceleration due to gravity,$g = 10 \, m/s^2$Let $t$ be the time taken to cover the vertical distance $h$. Using the equation of motion in the vertical direction:$h = u_y t + \frac{1}{2} g t^2$Since the man jumps horizontally,the initial vertical velocity $u_y = 0$.$9 = 0 	imes t + \frac{1}{2} 	imes 10 	imes t^2$$9 = 5 t^2$$t^2 = \frac{9}{5} = 1.8$$t = \sqrt{1.8} \approx 1.34 \, s$Now,calculate the horizontal distance $R$ covered by the man in this time:$R = u_x 	imes t = 9 	imes \sqrt{1.8} = 9 	imes 1.3416 \approx 12.07 \, m$Since the horizontal distance covered $(12.07 \, m)$ is greater than the distance between the buildings $(10 \, m)$,the man will be able to land on the next building.

Similar Questions

$A$ body is projected horizontally with a velocity of $4\,m/s$ from the top of a high tower. The velocity of the body after $0.7\,s$ is nearly $.....\,m/s$ (take $g=10\,m/s^2$).

$A$ fighter plane is flying horizontally at an altitude of $1.5\, km$ with a speed of $720\, km/h$. At what angle of sight (with respect to the horizontal) should the pilot drop the bomb when the target is seen,in order to hit the target?

From the top of a tower of height $40\,m$,a ball is projected upwards with a speed of $20\,m/s$ at an angle of elevation of $30^{\circ}$. The ratio of the total time taken by the ball to hit the ground to its time of flight (time taken to come back to the same elevation) is (take $g=10\,m/s^2$).

An airplane is flying at a height of $1960 \, m$ with a horizontal velocity of $360 \, km/hr$. When the airplane is directly above point $A$,a body is dropped from it. How much time (in $sec$) will it take for the body to reach the ground?

$A$ ball is thrown upward from the top of a building at an angle of $30^{\circ}$ to the horizontal with an initial speed of $15 \,ms^{-1}$. If the ball hits the ground after $3 \,s$, then the height of the building is (acceleration due to gravity $= 10 \,ms^{-2}$): (in $\,m$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module