A man walked diagonally across a square plot. | vedclass

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(C) Let the side of the square plot be $a$.Distance walked along the two edges $= a + a = 2a$.Distance walked along the diagonal $= a\sqrt{2}$.Distanc

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(C) Let the side of the square plot be $a$.Distance walked along the two edges $= a + a = 2a$.Distance walked along the diagonal $= a\sqrt{2}$.Distance saved $= 2a - a\sqrt{2} = a(2 - \sqrt{2})$.Percent saved $= \frac{	ext{Distance saved}}{	ext{Total distance along edges}} 	imes 100$.Percent saved $= \frac{a(2 - \sqrt{2})}{2a} 	imes 100 = \frac{2 - 1.414}{2} 	imes 100$.Percent saved $= \frac{0.586}{2} 	imes 100 = 0.293 	imes 100 = 29.3 \%$.Rounding to the nearest whole number,the percent saved is approximately $30 \%$.

$A$ man walked diagonally across a square plot. Approximately what was the percent saved by not walking along the edges?

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