A merchant has 435 litres,493 litres,and 551 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the least number of casks,the capacity of each cask must be the greatest possible value that divides $435$,$493$,and $551$ exactly. This c

Vedclass · Accepted Answer

$51$

Vedclass · Answer

(A) To find the least number of casks,the capacity of each cask must be the greatest possible value that divides $435$,$493$,and $551$ exactly. This capacity is the $H.C.F.$ of $435$,$493$,and $551$.First,find the $H.C.F.$ of $435$ and $493$:$493 = 435 	imes 1 + 58$$435 = 58 	imes 7 + 29$$58 = 29 	imes 2 + 0$So,the $H.C.F.$ of $435$ and $493$ is $29$.Now,check if $551$ is divisible by $29$:$551 \div 29 = 19$.Thus,the $H.C.F.$ of $435, 493,$ and $551$ is $29$.The capacity of each cask is $29$ litres.Total number of casks required $= (435 \div 29) + (493 \div 29) + (551 \div 29)$$= 15 + 17 + 19 = 51$.

$A$ merchant has $435$ litres,$493$ litres,and $551$ litres of three different kinds of milk. Find the least number of casks of equal size required to store all the milk without mixing.

Similar Questions

Find the side of the largest square slab which can be paved on the floor of a room $5 \, m \, 44 \, cm$ long and $3 \, m \, 74 \, cm$ broad.

Two numbers are in the ratio $3:4$. Their $L.C.M.$ is $84$. The greater number is

Let $N$ be the least six-digit number which,when divided by $4, 6, 10,$ and $15,$ leaves the same remainder of $2$ in each case. The sum of the digits in $N$ is:

The $HCF$ of $x^{8}-1$ and $x^{4}+2x^{3}-2x-1$ is

The $LCM$ of $2^{2} \times 3^{2} \times 5 \times 11$,$2^{4} \times 3^{4} \times 5^{2} \times 7$,and $2^{5} \times 3^{3} \times 5^{2} \times 7^{2} \times 11$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module