A metal ion M^{3+} after the loss of three el | vedclass

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(D) The initial oxidation state of the metal ion is $+3$. When an atom or ion loses electrons,its oxidation number increases. Since the ion $M^{3+}$ l

Vedclass · Accepted Answer

$6$

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(D) The initial oxidation state of the metal ion is $+3$. When an atom or ion loses electrons,its oxidation number increases. Since the ion $M^{3+}$ loses $3$ more electrons,the new oxidation number is calculated as: $3 + 3 = +6$. The reaction is represented as: $M^{3+} 	o M^{6+} + 3e^{-}$. Therefore,the final oxidation number is $6$.

$A$ metal ion $M^{3+}$ after the loss of three electrons in a reaction will have an oxidation number equal to

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