A metal rod of silver at 0^{circ}C is heated | vedclass

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Question

(A) Given: Initial length $L_0 = 100\, cm$,Change in temperature $\Delta 	heta = 100^{\circ}C - 0^{\circ}C = 100^{\circ}C$,Change in length $\Delta L

Vedclass · Accepted Answer

$5.7 	imes 10^{-5} {^{\circ}C^{-1}}$

Vedclass · Answer

(A) Given: Initial length $L_0 = 100\, cm$,Change in temperature $\Delta 	heta = 100^{\circ}C - 0^{\circ}C = 100^{\circ}C$,Change in length $\Delta L = 0.19\, cm$.First,calculate the coefficient of linear expansion $(\alpha)$:$\alpha = \frac{\Delta L}{L_0 \Delta 	heta} = \frac{0.19}{100 	imes 100} = \frac{0.19}{10000} = 1.9 	imes 10^{-5} {^{\circ}C^{-1}}$.Now,calculate the coefficient of cubical expansion $(\gamma)$:$\gamma = 3\alpha = 3 	imes 1.9 	imes 10^{-5} {^{\circ}C^{-1}} = 5.7 	imes 10^{-5} {^{\circ}C^{-1}}$.Therefore,the correct option is $A$.

$A$ metal rod of silver at $0^{\circ}C$ is heated to $100^{\circ}C$. Its length increases by $0.19\, cm$. If the original length of the rod is $100\, cm$,the coefficient of cubical expansion of the silver rod is:

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