A metallic ring connected to a rod oscillates | vedclass

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(D) When the metallic ring moves through the magnetic field,the magnetic flux linked with the ring changes. According to Faraday's law of electromagne

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come to rest very soon

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(D) When the metallic ring moves through the magnetic field,the magnetic flux linked with the ring changes. According to Faraday's law of electromagnetic induction,an electromotive force $(EMF)$ is induced in the ring. Since the ring is metallic,this induced $EMF$ causes eddy currents to flow within it. According to Lenz's law,these eddy currents produce a magnetic force that opposes the motion of the ring. This opposing force acts as a damping force,causing the kinetic energy of the pendulum to dissipate as heat due to the electrical resistance of the ring. Consequently,the amplitude of oscillation decreases rapidly,and the pendulum comes to rest very soon.

$A$ metallic ring connected to a rod oscillates freely like a pendulum. If a magnetic field is applied in the horizontal direction such that the pendulum swings through the field,the pendulum will:

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