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(B) The initial dimensions of the rectangular metallic sheet are $48\, m 	imes 36\, m$.When a square of side $8\, m$ is cut from each of the four cor

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$5120$

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(B) The initial dimensions of the rectangular metallic sheet are $48\, m 	imes 36\, m$.When a square of side $8\, m$ is cut from each of the four corners, the length and width of the base of the resulting open box are reduced by $2 	imes 8\, m = 16\, m$.New length of the base $= 48\, m - 16\, m = 32\, m$.New width of the base $= 36\, m - 16\, m = 20\, m$.The height of the box will be equal to the side of the square cut out, which is $8\, m$.Volume of the box $= 	ext{length} 	imes 	ext{width} 	imes 	ext{height} = 32\, m 	imes 20\, m 	imes 8\, m = 5120\, m^3$.

$A$ metallic sheet is of rectangular shape with dimensions $48\, m \times 36\, m$. From each of its corners, a square is cut off so as to make an open box. If the length of the side of the square is $8\, m$, the volume of the box (in $m^3$) is:

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