$A$ milliammeter of range $10 \, mA$ has a coil of resistance $1 \, \Omega$. To use it as a voltmeter of range $10 \, V$,the resistance that must be connected in series with it will be ............. $\Omega$.

  • A
    $999$
  • B
    $99$
  • C
    $1000$
  • D
    None of these

Explore More

Similar Questions

Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$,then the shunt resistance connected to the galvanometer is:

$A$ galvanometer has a resistance of $50 \ \Omega$ and it allows a maximum current of $5 \ mA$. It can be converted into a voltmeter to measure up to $100 \ V$ by connecting in series a resistor of resistance: (in $\Omega$)

$A$ galvanometer of resistance $G \ \Omega$ is shunted by a resistance $S \ \Omega$. To keep the main current in the circuit unchanged,the resistance to be connected in series with the galvanometer is

The deflection in a moving coil galvanometer is

$A$ voltmeter of resistance $20000\,\Omega$ reads $5 \text{ V}$. To make it read $20 \text{ V}$,the extra resistance required is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo