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(A) mixture of toluene and benzene forms an ideal solution. $p_{B}^{\circ}$ and $p_{T}^{\circ}$ are the vapour pressures of pure benzene and toluene,r

Vedclass · Accepted Answer

$p_{B}^{\circ} - p_{T}^{\circ}$

Vedclass · Answer

(A) mixture of toluene and benzene forms an ideal solution. $p_{B}^{\circ}$ and $p_{T}^{\circ}$ are the vapour pressures of pure benzene and toluene,respectively.According to Raoult's law,$p_{	ext{total}} = \chi_{B} p_{B}^{\circ} + \chi_{T} p_{T}^{\circ}$.We know that $\chi_{B} + \chi_{T} = 1$,so $\chi_{T} = 1 - \chi_{B}$.Substituting this into the equation: $p_{	ext{total}} = \chi_{B} p_{B}^{\circ} + (1 - \chi_{B}) p_{T}^{\circ}$.Rearranging the terms: $p_{	ext{total}} = p_{T}^{\circ} + (p_{B}^{\circ} - p_{T}^{\circ}) \chi_{B}$.Comparing this with the equation of a straight line $y = mx + c$,where $y = p_{	ext{total}}$ and $x = \chi_{B}$,the slope $m$ is equal to $(p_{B}^{\circ} - p_{T}^{\circ})$.

$A$ mixture of toluene and benzene forms a nearly ideal solution. Assume $p_{B}^{\circ}$ and $p_{T}^{\circ}$ to be the vapour pressures of pure benzene and toluene,respectively. The slope of the line obtained by plotting the total vapour pressure versus the mole fraction of benzene is $....$

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