A moving coil galvanometer has 100 equal divi | vedclass

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(D) The current sensitivity $I_s = 10 	ext{ divisions/mA}$.The voltage sensitivity $V_s = 2 	ext{ divisions/mV}$.The resistance of the galvanometer

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$9995$

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(D) The current sensitivity $I_s = 10 	ext{ divisions/mA}$.The voltage sensitivity $V_s = 2 	ext{ divisions/mV}$.The resistance of the galvanometer $G$ is given by $G = \frac{I_s}{V_s} = \frac{10 	ext{ div/mA}}{2 	ext{ div/mV}} = 5 \ \Omega$.The full-scale deflection current $I_g$ for $100$ divisions is $I_g = \frac{100 	ext{ divisions}}{10 	ext{ divisions/mA}} = 10 	ext{ mA} = 0.01 	ext{ A}$.We want the galvanometer to read $1 	ext{ V}$ per division. For $100$ divisions,the total voltage $V$ required is $V = 100 	imes 1 	ext{ V} = 100 	ext{ V}$.Let the series resistance be $R$. Then $V = I_g(G + R)$.$100 = 0.01(5 + R)$.$10000 = 5 + R$.$R = 10000 - 5 = 9995 \ \Omega$.

$A$ moving coil galvanometer has $100$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \ V$,the resistance in Ohm's needed to be connected in series with the coil will be

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