A normal girl, whose mother is haemophilic, m | vedclass

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(B) Haemophilia is an $X$-linked recessive disorder.Let $X^H$ be the normal allele and $X^h$ be the haemophilic allele.The mother of the girl is haemo

Vedclass · Accepted Answer

$(b)$ and $(c)$ only

Vedclass · Answer

(B) Haemophilia is an $X$-linked recessive disorder.Let $X^H$ be the normal allele and $X^h$ be the haemophilic allele.The mother of the girl is haemophilic $(X^h X^h)$, so she must pass one $X^h$ chromosome to her daughter. Since the girl is phenotypically normal, her genotype must be $X^H X^h$ (carrier).The male has no ancestral history of haemophilia, so his genotype is $X^H Y$.Cross: $X^H X^h$ (carrier female) $	imes$ $X^H Y$ (normal male).Offspring genotypes: $X^H X^H$ (normal daughter), $X^H X^h$ (carrier daughter), $X^H Y$ (normal son), $X^h Y$ (haemophilic son).Possible phenotypes: Normal daughter, carrier daughter, normal son, and haemophilic son.Comparing these with the given statements: Statement $(b)$ includes haemophilic son and carrier daughter. Statement $(c)$ includes normal daughter and normal son. Both are present in the offspring. Thus, options $(b)$ and $(c)$ are correct.

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