A nucleus _n^mX emits one alpha particle and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The initial nucleus is given as $_n^mX$, where $m$ is the mass number and $n$ is the atomic number.An $\alpha$ particle is a helium nucleus, denot

Vedclass · Accepted Answer

$_{n}^{m-4}Z$

Vedclass · Answer

(B) The initial nucleus is given as $_n^mX$, where $m$ is the mass number and $n$ is the atomic number.An $\alpha$ particle is a helium nucleus, denoted as $_2^4He$. When a nucleus emits an $\alpha$ particle, the mass number decreases by $4$ and the atomic number decreases by $2$.After emitting one $\alpha$ particle, the nucleus becomes $_{n-2}^{m-4}X'$.$A$ $\beta^-$ particle is an electron, denoted as $_{-1}^0e$. When a nucleus emits a $\beta^-$ particle, the mass number remains unchanged and the atomic number increases by $1$.Since two $\beta^-$ particles are emitted, the atomic number increases by $2 	imes 1 = 2$.The final atomic number is $(n-2) + 2 = n$.The final mass number is $m-4$.Thus, the resulting nucleus is $_n^{m-4}Z$.

$A$ nucleus $_n^mX$ emits one $\alpha$ particle and two $\beta^-$ particles. The resulting nucleus is

Similar Questions

$A$ radioactive element emits two $\beta$-particles and one $\alpha$-particle. The resulting daughter nucleus is ...

In a radioactive reaction $_{92}X^{232} \to _{82}Y^{204}$,the number of $\alpha$-particles emitted is:

An element $A$ decays into element $C$ by a two-step process:
$A \to B + {\;_2}He^4$
$B \to C + 2e^-$
Then:

Beta rays emitted by a radioactive material are

Vedclass Test Series

Exam Paper Generator

Online Exam Module