A nucleus X undergoes the following transform | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the nucleus $X$ be represented as $_{Z}^{A}X$.$1$. When $X$ undergoes $\alpha$-decay,it emits an $\alpha$-particle $(_{2}^{4}He)$. The new nuc

Vedclass · Accepted Answer

$X$ and $Z$ are isotopes

Vedclass · Answer

(D) Let the nucleus $X$ be represented as $_{Z}^{A}X$.$1$. When $X$ undergoes $\alpha$-decay,it emits an $\alpha$-particle $(_{2}^{4}He)$. The new nucleus $Y$ will have an atomic number $Z-2$ and a mass number $A-4$:$_{Z}^{A}X \xrightarrow{\alpha} _{Z-2}^{A-4}Y + _{2}^{4}He$$2$. When $Y$ undergoes $2\beta$-decay,it emits two $\beta$-particles (electrons,$_{-1}^{0}e$). Each $\beta$-decay increases the atomic number by $1$ without changing the mass number:$_{Z-2}^{A-4}Y \xrightarrow{2\beta} _{Z-2+2}^{A-4}Z + 2_{-1}^{0}e$$3$. The resulting nucleus $Z$ is $_{Z}^{A-4}Z$.Comparing $X$ $(_{Z}^{A}X)$ and $Z$ $(_{Z}^{A-4}Z)$,we see they have the same atomic number $Z$ but different mass numbers. Therefore,$X$ and $Z$ are isotopes.

$A$ nucleus $X$ undergoes the following transformation:
$X \xrightarrow{\alpha} Y$
$Y \xrightarrow{2\beta} Z$
Then:

Similar Questions

An $U^{238}$ nucleus is initially at rest. It decays by emitting an $\alpha$-particle with speed $u$. Find the recoil speed of the daughter nucleus.

Three $\alpha$-particles and one $\beta$-particle decay take place in series from an isotope $_{88}Ra^{238}$. Finally,the isotope obtained will be:

$A$ free neutron decays spontaneously into:

The nucleus produced due to $\alpha$-decay of the nucleus $_Z{X^A}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ nucleus $X$ undergoes the following transformation:$X \xrightarrow{\alpha} Y$$Y \xrightarrow{2\beta} Z$Then: